The general equation of a line is y =mx+c it is called slope intercept form of that line. Here m represent the slope of the line and c is the y intercept .here we are going to learn about how to write slope intercept form and its example problems.
For example:
y- 3x = 6
The slope intercept form is y =mx+b
-3x moves to right hand side so it will be 3x
Therefore slope intercept form y =3x+6
I like to share this slope of the line with you all through my article.
Example problems to write in slope intercept form:
Write the equation of a straight line in slope intercept form whose slope = 3 and passes through the point (-1,-6).
Solution:
We know that general equation of a line y=mx+b
Here
m=3
x=-1
y=-6
Substitute all the value in the general equation
-6 = 3(-1) +b
-6 =-3 +b
Add both sides +3b
-6 +3 =-3+3 +b
b=-3
Substitute the y intercept value in the general equation,
y=3x-3
There the equation of straight line is y=3x-3
Writing equations in slope intercept form:
Write the slope intercept form of the line that the line passes through the points (2, 3) (5, 6)
Solution:
We want to find the equation for a line that passes through the two points:
(2, 3) and (5, 6).
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope
slope intercept form
First, let's find what m is, the slope of the line...
For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:
m = `(y2-y1) / (x2-x1)`
Here,
x1=2 and y1=3.
x2=5 and y2=6.
Now, just plug the numbers into the formula for m above, like this:
m=`(6-3)/(5-2)`
m=`3/3`
m=1
Therefore the slope of the given line is 1
Algebra is widely used in day to day activities watch out for my forthcoming posts on Solving Special Right Triangles and cbse syllabus for class 9. I am sure they will be helpful.
Slope intercept form = y=mx+b
x=2 and y =3
So
3=1*2+b
3=2+b
b=3-2
b=1
Therefore the slope intercept form y=x-1
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