Pyramid is a solid whose base is a planar polygon with a triangular
face on each side. These triangular faces meet in a point which is not
in the plane fo the base. Pentagonal pyramid is pyramid whose base is a
pentagon, and having 5 triangular faces on each side.
Pentagonal Pyramid Formula:
Let, a = apothem length, s,b = side, h = height and l = slant height,
Properties of pentagonal pyramid:
1) Find volume and surface area of a pentagonal pyramid with the given apothem length 7, side 8, height 9 and the slant height 10.
Solution: a = 7, s = b = 8, h = 9, l = 10
Step 1: Area of the base(A) = `(5/2) axx s`
= 2.5 * 7 * 8
= 2.5 * 56
= 140
Step 2: Surface Area of Pyramid = `A + (5/2) s xxl`
= 140 + ((5/2) * 8 * 10
= 140 + (2.5 * 80)
= 140 + 200
= 340
Step 4: Volume of Pyramid =`(5/6) a xx b xxh`
= `(5/6)` * 7 * 8 * 9
= (0.833) * 56*9
= 0.8333 * 504
= 419.98
2) Find the surface area a pentagonal pyramid with the given apothem length 2.5, side 5 and the slant height 9.
Solution: a = 2.5, s = b = 5, , l = 9
Area of the base(A) = `(5/2)axxs`
= 2.5 * 2.5 * 5
= 6.25 * 5
= 31.25
Surface Area of Pyramid = `A + (5/2) s xxl`
= 31.25 + ((5/2) *5 * 9
= 31.25 + (2.5 * 45)
= 31.25+ 112.5
= 143.75
Algebra is widely used in day to day activities watch out for my forthcoming posts on Mean Median Mode Definition and icse syllabus 2013. I am sure they will be helpful.
Pentagonal Pyramid Formula:
Let, a = apothem length, s,b = side, h = height and l = slant height,
- Area of Base(A) = `(5/2)axxs`
- Surface Area of Pyramid = `(5/2) a xx s + (5/2) s xx l = A + (5/2) s xx l`
- Volume of Pyramid = `(5/6) axxbxxh`
Properties of pentagonal pyramid:
- A pentagonal pyramid has 6 faces. One base and 5 lateral faces
- A pentagonal pyramid has 10 edges
- A pentagonal pyramid has 6 corners
Examples on pentagonal pyramid:
1) Find volume and surface area of a pentagonal pyramid with the given apothem length 7, side 8, height 9 and the slant height 10.
Solution: a = 7, s = b = 8, h = 9, l = 10
Step 1: Area of the base(A) = `(5/2) axx s`
= 2.5 * 7 * 8
= 2.5 * 56
= 140
Step 2: Surface Area of Pyramid = `A + (5/2) s xxl`
= 140 + ((5/2) * 8 * 10
= 140 + (2.5 * 80)
= 140 + 200
= 340
Step 4: Volume of Pyramid =`(5/6) a xx b xxh`
= `(5/6)` * 7 * 8 * 9
= (0.833) * 56*9
= 0.8333 * 504
= 419.98
2) Find the surface area a pentagonal pyramid with the given apothem length 2.5, side 5 and the slant height 9.
Solution: a = 2.5, s = b = 5, , l = 9
Area of the base(A) = `(5/2)axxs`
= 2.5 * 2.5 * 5
= 6.25 * 5
= 31.25
Surface Area of Pyramid = `A + (5/2) s xxl`
= 31.25 + ((5/2) *5 * 9
= 31.25 + (2.5 * 45)
= 31.25+ 112.5
= 143.75
Algebra is widely used in day to day activities watch out for my forthcoming posts on Mean Median Mode Definition and icse syllabus 2013. I am sure they will be helpful.
Pictures of pentagonal pyramid
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