A trigonometric equation is an equation involving the trigonometric function or function of unknown angles, e.g., sin x = 0, cos2x-sinx=1/4, sin( theta + 1/4) = ½, etc are all trigonometric equations.
A solution of a trigonometric equation is a value of that unknown angle that satisfies the equation. Trigonometric equation may have an unlimited number of solution, e.g., sin x =0,pi2pi3pi
Let us learn how to solve trigonometric equations.
how to solve the trigonometric equation step by step:
Type 1: Equation in which only one function of a single angle is involved.
Procedure. Solve algebraically for the values of the function
Solve for x, sin x = (sqrt(-3))/(2)(0≤x≤2π)
solution:
sin x = (sqrt3)/(2) = - sin 60°
= sin (180° + 60°)
= sin (360° - 60°)
rArr x = 240°,300°
Type 2. Equation expressible in terms of one t- ratio of the unknown angle
Procedure. The following formulas help in expressing all the t-functins in terms of a single t-function.
Square relations
Solve cos2 theta -sintheta - 1/4 = 0(0°<= theta360°)
cos2 theta -sintheta - 1/4=0
1 - sin2 theta- sintheta 1/4=0
4sin2theta +4 sintheta -3=0
hence, 2 sin theta + 3 = 0 sin theta
This value is inadmissible
theta = 30°,150°
Type 3 Equation involving multiple angles.
Case-I When the equation involves only one multiple angle.
solve sin 3x = - 1/sqrt(2) ,0<= <= 2pi
Solution since we require x such that 0<= <= 2pimust be such that 0<=3x <=6pi
3x = 5pi/4 ,7pi /4 , 13pi 15pi 21pi 23pi
= 5pi/4 ,7pi /4 , 13pi /4 ,15pi /4 ,21pi /4 , 23pi
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Case-2 Equation involving two multiple angles
They are like
sin ntheta = sin m theta
sin ntheta = cos mtheta
How to solve trigonometric equations involving compound angles.
Solve the cos x - sqrt(3) sin x = 1,0° <= x <= 0°
Solution: Dividing both sides of the equation by sqrt({(1)2) +(sqrt(3)2 }
=> cos60° cosx - sin 60°sin x = 1/2
=> cos(x + 60°)= cos60° or cos(360° - 60°)
x + 60° = 60° or 300° => x = 0°,240°
Taking values such that 0°<= x <= 360°.
Hence proved
The above problems says how to solve trigonometric equations.
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